393 E@yLv=40,xCxPT,ID:9c.00CRpcDY4Acoca3GMVyTYp12VJHswC0EA3NGvrtHeaMz 2024/07/27(y) 21:16:23 ID:7DOJb1NZ
h=vsinΖt-(1/2)gt^2 -0.4=5*(1000/3600)*sin45*t-(1/2)gt^2 tΰ0.4 l=vcosΖt l=5*(1000/3600)*cos45*0.4ΰ0.392[m]39.2[cm]