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393 ”E–@’ŸyLv=40,xCxPT,ID:9c.00CRpcDY4Acoca3GMVyTYp12VJHswC0EA3NGvrtHeaMz 2024/07/27(“y) 21:16:23 ID:7DOJb1NZ

h=vsinƒΖt-(1/2)gt^2
-0.4=5*(1000/3600)*sin45‹*t-(1/2)gt^2
tΰ0.4

l=vcosƒΖt
l=5*(1000/3600)*cos45‹*0.4ΰ0.392[m]39.2[cm]